Gits2012teaser
From Fixme.ch
#1 TelAviv
What is the password? (File)
Hint: TeLaViv+ is a packet forensics challenge.
#2 AL's Revenge
- file 49dd327824d5afe9cdf931ea4b13719f.bin says xz compressed file -> xzcat > f
- file f says LLVM bitcode -> llvm-dis > f.s (only works with LLVM 2.8, not with 3.0)
- analyze disassembly, extract C representation:
int VerifySerial(uint64_t name, uint64_t serial) { uint64_t a = 0x8000000000000000LL; uint64_t b = 0xa348fccd93aea5a7LL; uint64_t result = 0; /* high order bit set? */ if (name & a) a ^= b; if (serial & a) serial ^= b; while (serial != 0) { if (serial & 1) result ^= name; serial >>= 1; name <<= 1; if (name & a) name ^= b; }H return (result == 1); }
- it looks like a multiplication over a galois field, with the irreducible polynomial 0x1a348fccd93aea5a7 (note leading bit not in C), but it actually isn't, because the high bit gets checked after the shift, not before.
- lacking math knowledge and math package fu, decided to treat the problem as a linear equation system:
- The shifting and xoring produces a set of integers, call them name_i. If the serial bit s_i is set, name_i gets added to the result. So you can roughly say r = N * s, with r being the result vector, s the serial vector and N the names matrix.
- lacking math package fu, implement a gaussian elimination manually:
class Numeric def bits64 sprintf("%064b", self).each_char.map{|c| c == "0" ? 0 : 1} end end def names(name) p = 0xa348fccd93aea5a7 if (name >> 63) & 1 == 1 name ^= p end ([name] + 63.times.map do |i| name <<= 1 if (name >> 63) & 1 == 1 name ^= p end name end).map(&:bits64) end class Array def pivot res = [] self[0].size.times.map do |i| self.size.times.map do |j| self[j][i] end end end def bitary_to_int self.join.to_i(2) end end class Eq < Array attr_accessor :res def initialize(ary, res) self.replace(ary) @res = res end def lead_zero self.take_while{|e| e == 0} end def first_pos self.index(1) end def subtract(o) Eq.new(self.zip(o).map{|aa, bb| aa ^ bb}, @res ^ o.res) end end class EqSys < Array def initialize(ary, res=nil) if !(Eq === ary[0]) && !ary.empty? ary = ary.zip(res).map{|a, r| Eq.new(a, r)} end self.replace(ary) end def sort_by_zeros self.sort do |a, b| a.lead_zero <=> b.lead_zero end end def subtract_eq(eq) pos = eq.first_pos return self if not pos EqSys.new(self.map{|e| e[pos] == 1 ? e.subtract(eq) : e}) end def elim front = EqSys.new([]) cur = nil rest = self.sort_by_zeros while not rest.empty? front << cur if cur cur = rest.shift front = front.subtract_eq(cur) rest = rest.subtract_eq(cur) rest = rest.sort_by_zeros end front << cur front end def to_s self.map{|e| e.map(&:to_s).join + " = #{e.res}"}.join("\n") end end require 'pp' if __FILE__ == $0 ns = names(0x6638623261336134) pv = ns.pivot es = EqSys.new(pv, 1.bits64) puts es.to_s puts r = es.elim puts r.to_s res = r.map{|e| e.res}.reverse puts res.bitary_to_int.to_s(16) s0 = r.pivot.last.reverse puts s0.bitary_to_int.to_s(16) puts (res.bitary_to_int^s0.bitary_to_int).to_s(16) end