Difference between revisions of "Extension Explorer 16"

From Fixme.ch
Jump to: navigation, search
(LED's for crossroad)
(Formula)
Line 39: Line 39:
  
 
* calculation of resistance R_LED_G <math>\frac{U_r}{I} = \frac{VDD - U_{LG}}{I} = \frac{3.3V - 2.2V}{10mA}</math> = ''' 110 ohm '''
 
* calculation of resistance R_LED_G <math>\frac{U_r}{I} = \frac{VDD - U_{LG}}{I} = \frac{3.3V - 2.2V}{10mA}</math> = ''' 110 ohm '''
* power dispersed by the resistance R_LED_O <math>\frac{R_LED_O^{2}}{I} = \frac{110 o ^{2}}{10mA}</math> = ''' 11 mW '''
+
* power dispersed by the resistance R_LED_G <math>\frac{R_LED_G^{2}}{I} = \frac{110 o ^{2}}{10mA}</math> = ''' 11 mW '''
  
 
= Layout =
 
= Layout =

Revision as of 23:04, 29 September 2014

Description

In French: Création d'une carte d'extension pour la carte Explorer (PROJET: Carte Explorer 16 & Exos sur les uC).

  • V1: un montage permettra de simuler un carrefour routier, composer de 4 feux (RGB)


in English: creation of one extansion board for the Explorer Board (see the links above)

  • V1: assembly will allow to simulate a crossroad (4 fires (RGB))

Digram - Schematic

Part Calculation of Electronics Digram

LED's for crossroad

  • the datasheet of the DSP implemented on the Explorer Board 16 (see pages 1 & 273) indicates that :
    • output current of I/O : I = 10mA
    • voltage I/O : VDD = 3.3V
  • the datasheet of the red LED (see pages 3) indicates that :
    • conduction voltage : ULR = VF = 1.8V
    • average current : I = 20mA
  • the datasheet of the orange LED (see pages 3 / 4 / 5) indicates that :
    • conduction voltage : ULO = VF = 1.9V
    • average current : I = 30mA
  • the datasheet of the green LED (see pages 3 / 4 / 5) indicates that :
    • conduction voltage : ULG = VF = 2.2V
    • average current : I = 30mA

Formula

  • calculation of resistance R_LED_R \frac{U_r}{I} = \frac{VDD - U_{LR}}{I} = \frac{3.3V - 1.8V}{10mA} = 150 ohm
  • power dispersed by the resistance R_LED_R \frac{R_LED_R^{2}}{I} = \frac{150 o ^{2}}{10mA} = 15 mW
  • calculation of resistance R_LED_O \frac{U_r}{I} = \frac{VDD - U_{LO}}{I} = \frac{3.3V - 1.9V}{10mA} = 140 ohm
  • power dispersed by the resistance R_LED_O \frac{R_LED_O^{2}}{I} = \frac{140 o ^{2}}{10mA} = 14 mW
  • calculation of resistance R_LED_G \frac{U_r}{I} = \frac{VDD - U_{LG}}{I} = \frac{3.3V - 2.2V}{10mA} = 110 ohm
  • power dispersed by the resistance R_LED_G \frac{R_LED_G^{2}}{I} = \frac{110 o ^{2}}{10mA} = 11 mW

Layout

Components listing

Modification

Documentation

PDF FILE

required links

Contributor