RIN_{low} = \frac{VDD_{low}}{I_L} = \frac{0.66}{2u}
</math>
= ''' 330 kohmskΩ'''
* Resitor Pull-Up MAX :
R_{Pull-Up_{max}} = \frac{VDD - VDD_{low}}{I_L} = \frac{3.3 - 0.66}{2u}
</math>
= ''' 1.32 MohmsMΩ'''
''Remark'' : the resistor must be more less that the R_PULL-UP_max - usually, the value of 10kohm is using for the resistor pull-up.